Base | Representation |
---|---|
bin | 111101000001010111… |
… | …0000111010011110011 |
3 | 110112020112220201112011 |
4 | 1322002232013103303 |
5 | 4121333242124043 |
6 | 140111103543351 |
7 | 12316226600332 |
oct | 1720256072363 |
9 | 415215821464 |
10 | 131042145523 |
11 | 50635969523 |
12 | 214918bab57 |
13 | c484a79ca3 |
14 | 64b1a67d19 |
15 | 361e5bc59d |
hex | 1e82b874f3 |
131042145523 has 4 divisors (see below), whose sum is σ = 131417624800. Its totient is φ = 130666666248.
The previous prime is 131042145497. The next prime is 131042145529. The reversal of 131042145523 is 325541240131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131042145523 - 29 = 131042145011 is a prime.
It is a super-2 number, since 2×1310421455232 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131042145529) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 187739115 + ... + 187739812.
It is an arithmetic number, because the mean of its divisors is an integer number (32854406200).
Almost surely, 2131042145523 is an apocalyptic number.
131042145523 is a deficient number, since it is larger than the sum of its proper divisors (375479277).
131042145523 is an equidigital number, since it uses as much as digits as its factorization.
131042145523 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 375479276.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 131042145523 its reverse (325541240131), we get a palindrome (456583385654).
The spelling of 131042145523 in words is "one hundred thirty-one billion, forty-two million, one hundred forty-five thousand, five hundred twenty-three".
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