1310422113433 has 4 divisors (see below), whose sum is σ = 1310486128740. Its totient is φ = 1310358098128.

The previous prime is 1310422113391. The next prime is 1310422113443. The reversal of 1310422113433 is 3343112240131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1045246551129 + 265175562304 = 1022373^2 + 514952^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310422113433 - 2⁹ = 1310422112921 is a prime.

It is a super-2 number, since 2×1310422113433² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310422113443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31976938 + ... + 32017891.

It is an arithmetic number, because the mean of its divisors is an integer number (327621532185).

Almost surely, 2^{1310422113433} is an apocalyptic number.

It is an amenable number.

1310422113433 is a deficient number, since it is larger than the sum of its proper divisors (64015307).

1310422113433 is an equidigital number, since it uses as much as digits as its factorization.

1310422113433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 64015306.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1310422113433 its reverse (3343112240131), we get a palindrome (4653534353564).

The spelling of 1310422113433 in words is "one trillion, three hundred ten billion, four hundred twenty-two million, one hundred thirteen thousand, four hundred thirty-three".