13104333020011 has 4 divisors (see below), whose sum is σ = 13458504182752. Its totient is φ = 12750161857272.

The previous prime is 13104333019961. The next prime is 13104333020039. The reversal of 13104333020011 is 11002033340131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13104333020011 - 2¹⁷ = 13104332888939 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13104333020071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 177085581315 + ... + 177085581388.

It is an arithmetic number, because the mean of its divisors is an integer number (3364626045688).

Almost surely, 2^{13104333020011} is an apocalyptic number.

13104333020011 is a deficient number, since it is larger than the sum of its proper divisors (354171162741).

13104333020011 is an equidigital number, since it uses as much as digits as its factorization.

13104333020011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 354171162740.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 13104333020011 its reverse (11002033340131), we get a palindrome (24106366360142).

The spelling of 13104333020011 in words is "thirteen trillion, one hundred four billion, three hundred thirty-three million, twenty thousand, eleven".