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131043866041 = 1111913078731
BaseRepresentation
bin111101000001011010…
…0101011010110111001
3110112020200011010122001
41322002310223112321
54121334212203131
6140111204501001
712316250324404
oct1720264532671
9415220133561
10131043866041
1150636934140
12214923aa761
13c48523014a
1464b1d94d3b
15361e80c261
hex1e82d2b5b9

131043866041 has 4 divisors (see below), whose sum is σ = 142956944784. Its totient is φ = 119130787300.

The previous prime is 131043866017. The next prime is 131043866047. The reversal of 131043866041 is 140668340131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131043866041 - 215 = 131043833273 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131043866047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5956539355 + ... + 5956539376.

It is an arithmetic number, because the mean of its divisors is an integer number (35739236196).

Almost surely, 2131043866041 is an apocalyptic number.

131043866041 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

131043866041 is a deficient number, since it is larger than the sum of its proper divisors (11913078743).

131043866041 is a wasteful number, since it uses less digits than its factorization.

131043866041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11913078742.

The product of its (nonzero) digits is 41472, while the sum is 37.

The spelling of 131043866041 in words is "one hundred thirty-one billion, forty-three million, eight hundred sixty-six thousand, forty-one".

Divisors: 1 11 11913078731 131043866041