Base | Representation |
---|---|
bin | 11000011010001010… |
… | …10101001100101001 |
3 | 1020211021020122210012 |
4 | 30031011111030221 |
5 | 203314211400431 |
6 | 10004200501305 |
7 | 642511406156 |
oct | 141505251451 |
9 | 36737218705 |
10 | 13104403241 |
11 | 5615104126 |
12 | 265877a835 |
13 | 130abc7777 |
14 | 8c458522d |
15 | 51a6c622b |
hex | 30d155329 |
13104403241 has 4 divisors (see below), whose sum is σ = 13113435984. Its totient is φ = 13095370500.
The previous prime is 13104403219. The next prime is 13104403243. The reversal of 13104403241 is 14230440131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14230440131 = 359 ⋅39639109.
It is a cyclic number.
It is not a de Polignac number, because 13104403241 - 210 = 13104402217 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13104403243) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4514195 + ... + 4517096.
It is an arithmetic number, because the mean of its divisors is an integer number (3278358996).
Almost surely, 213104403241 is an apocalyptic number.
It is an amenable number.
13104403241 is a deficient number, since it is larger than the sum of its proper divisors (9032743).
13104403241 is an equidigital number, since it uses as much as digits as its factorization.
13104403241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9032742.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 13104403241 its reverse (14230440131), we get a palindrome (27334843372).
The spelling of 13104403241 in words is "thirteen billion, one hundred four million, four hundred three thousand, two hundred forty-one".
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