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13104405130051 = 37431801820223
BaseRepresentation
bin1011111010110001101101…
…1010011010101101000011
31201101202202112011122221001
42332230123122122231003
53204200310203130201
643512025224512431
72521522242512554
oct276543332325503
951352675148831
1013104405130051
1141a2602079244
12157787a91b717
13740981005b91
1433438413832b
1517ad204c0301
hexbeb1b69ab43

13104405130051 has 8 divisors (see below), whose sum is σ = 13458625818624. Its totient is φ = 12750186945600.

The previous prime is 13104405130039. The next prime is 13104405130121. The reversal of 13104405130051 is 15003150440131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13104405130051 - 27 = 13104405129923 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13104405730051) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15566526 + ... + 16386748.

It is an arithmetic number, because the mean of its divisors is an integer number (1682328227328).

Almost surely, 213104405130051 is an apocalyptic number.

13104405130051 is a deficient number, since it is larger than the sum of its proper divisors (354220688573).

13104405130051 is an equidigital number, since it uses as much as digits as its factorization.

13104405130051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1252061.

The product of its (nonzero) digits is 3600, while the sum is 28.

Adding to 13104405130051 its reverse (15003150440131), we get a palindrome (28107555570182).

The spelling of 13104405130051 in words is "thirteen trillion, one hundred four billion, four hundred five million, one hundred thirty thousand, fifty-one".

Divisors: 1 37 431801 820223 15976637 30348251 354173111623 13104405130051