131044251002299 has 4 divisors (see below), whose sum is σ = 131044429477080. Its totient is φ = 131044072527520.

The previous prime is 131044251002297. The next prime is 131044251002303. The reversal of 131044251002299 is 992200152440131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131044251002299 - 2¹ = 131044251002297 is a prime.

It is a super-2 number, since 2×131044251002299² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131044251002297) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88131454 + ... + 89606035.

It is an arithmetic number, because the mean of its divisors is an integer number (32761107369270).

Almost surely, 2^{131044251002299} is an apocalyptic number.

131044251002299 is a deficient number, since it is larger than the sum of its proper divisors (178474781).

131044251002299 is an equidigital number, since it uses as much as digits as its factorization.

131044251002299 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 178474780.

The product of its (nonzero) digits is 155520, while the sum is 43.

The spelling of 131044251002299 in words is "one hundred thirty-one trillion, forty-four billion, two hundred fifty-one million, two thousand, two hundred ninety-nine".