Base | Representation |
---|---|
bin | 11101110010111100100010… |
… | …111000001011100101100001 |
3 | 122011222201022211111222002011 |
4 | 131302330202320023211201 |
5 | 114134012243033233441 |
6 | 1142412533555552521 |
7 | 36413432501031232 |
oct | 3562744270134541 |
9 | 564881284458064 |
10 | 131044332321121 |
11 | 3883365330513a |
12 | 128453298bb741 |
13 | 581757332b0ab |
14 | 2450818311089 |
15 | 1023b6cd12581 |
hex | 772f22e0b961 |
131044332321121 has 8 divisors (see below), whose sum is σ = 131935729406400. Its totient is φ = 130153093968432.
The previous prime is 131044332321017. The next prime is 131044332321157. The reversal of 131044332321121 is 121123233440131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131044332321121 - 211 = 131044332319073 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131044332328121) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38026165 + ... + 41328898.
It is an arithmetic number, because the mean of its divisors is an integer number (16491966175800).
Almost surely, 2131044332321121 is an apocalyptic number.
It is an amenable number.
131044332321121 is a deficient number, since it is larger than the sum of its proper divisors (891397085279).
131044332321121 is a wasteful number, since it uses less digits than its factorization.
131044332321121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 79366295.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 131044332321121 its reverse (121123233440131), we get a palindrome (252167565761252).
The spelling of 131044332321121 in words is "one hundred thirty-one trillion, forty-four billion, three hundred thirty-two million, three hundred twenty-one thousand, one hundred twenty-one".
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