Search a number
-
+
13104451001321 = 79165879126599
BaseRepresentation
bin1011111010110001111000…
…1001011001101111101001
31201101202212201111011110222
42332230132021121233221
53204200403424020241
643512033544015425
72521523340433211
oct276543611315751
951352781434428
1013104451001321
1141a2625a59a89
121577892161575
1374098a676c44
1433438a279241
1517ad24531a4b
hexbeb1e259be9

13104451001321 has 4 divisors (see below), whose sum is σ = 13270330128000. Its totient is φ = 12938571874644.

The previous prime is 13104451001293. The next prime is 13104451001339. The reversal of 13104451001321 is 12310015440131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13104451001321 - 222 = 13104446807017 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13104451003321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82939563221 + ... + 82939563378.

It is an arithmetic number, because the mean of its divisors is an integer number (3317582532000).

Almost surely, 213104451001321 is an apocalyptic number.

It is an amenable number.

13104451001321 is a deficient number, since it is larger than the sum of its proper divisors (165879126679).

13104451001321 is an equidigital number, since it uses as much as digits as its factorization.

13104451001321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 165879126678.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 13104451001321 its reverse (12310015440131), we get a palindrome (25414466441452).

The spelling of 13104451001321 in words is "thirteen trillion, one hundred four billion, four hundred fifty-one million, one thousand, three hundred twenty-one".

Divisors: 1 79 165879126599 13104451001321