Base | Representation |
---|---|
bin | 1011111010110010001001… |
… | …0001011000111111010011 |
3 | 1201101210001112201001001011 |
4 | 2332230202101120333103 |
5 | 3204201024133013433 |
6 | 43512044455151351 |
7 | 2521525140600046 |
oct | 276544221307723 |
9 | 51353045631034 |
10 | 13104520204243 |
11 | 41a2661026186 |
12 | 15778b1375557 |
13 | 74099bac6a10 |
14 | 334395530c5d |
15 | 17ad2a6513cd |
hex | beb22458fd3 |
13104520204243 has 16 divisors (see below), whose sum is σ = 14868100154880. Its totient is φ = 11449969411104.
The previous prime is 13104520204241. The next prime is 13104520204297. The reversal of 13104520204243 is 34240202540131.
It is a cyclic number.
It is not a de Polignac number, because 13104520204243 - 21 = 13104520204241 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13104520204241) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22522171 + ... + 23096692.
It is an arithmetic number, because the mean of its divisors is an integer number (929256259680).
Almost surely, 213104520204243 is an apocalyptic number.
13104520204243 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13104520204243 is a deficient number, since it is larger than the sum of its proper divisors (1763579950637).
13104520204243 is a wasteful number, since it uses less digits than its factorization.
13104520204243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45620058.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 13104520204243 its reverse (34240202540131), we get a palindrome (47344722744374).
The spelling of 13104520204243 in words is "thirteen trillion, one hundred four billion, five hundred twenty million, two hundred four thousand, two hundred forty-three".
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