Base | Representation |
---|---|
bin | 11101110010111101011001… |
… | …000111000110010111001001 |
3 | 122011222210200020121200101010 |
4 | 131302331121013012113021 |
5 | 114134021124000422140 |
6 | 1142413204141514133 |
7 | 36413464156630650 |
oct | 3562753107062711 |
9 | 564883606550333 |
10 | 131045242201545 |
11 | 38833a7a975831 |
12 | 12845542572949 |
13 | 58176899a3a89 |
14 | 24508a30c0197 |
15 | 1023bc2b41880 |
hex | 772f591c65c9 |
131045242201545 has 16 divisors (see below), whose sum is σ = 239625585740160. Its totient is φ = 59906396434944.
The previous prime is 131045242201513. The next prime is 131045242201561. The reversal of 131045242201545 is 545102242540131.
It is not a de Polignac number, because 131045242201545 - 25 = 131045242201513 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 624024962760 + ... + 624024962969.
It is an arithmetic number, because the mean of its divisors is an integer number (14976599108760).
Almost surely, 2131045242201545 is an apocalyptic number.
131045242201545 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
131045242201545 is a deficient number, since it is larger than the sum of its proper divisors (108580343538615).
131045242201545 is a wasteful number, since it uses less digits than its factorization.
131045242201545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1248049925744.
The product of its (nonzero) digits is 192000, while the sum is 39.
Adding to 131045242201545 its reverse (545102242540131), we get a palindrome (676147484741676).
The spelling of 131045242201545 in words is "one hundred thirty-one trillion, forty-five billion, two hundred forty-two million, two hundred one thousand, five hundred forty-five".
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