131045435333353 has 4 divisors (see below), whose sum is σ = 138753990352980. Its totient is φ = 123336880313728.

The previous prime is 131045435333317. The next prime is 131045435333473. The reversal of 131045435333353 is 353333534540131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 54977523990489 + 76067911342864 = 7414683^2 + 8721692^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131045435333353 is a prime.

It is a super-2 number, since 2×131045435333353² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131045435339353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3854277509788 + ... + 3854277509821.

It is an arithmetic number, because the mean of its divisors is an integer number (34688497588245).

Almost surely, 2^{131045435333353} is an apocalyptic number.

It is an amenable number.

131045435333353 is a deficient number, since it is larger than the sum of its proper divisors (7708555019627).

131045435333353 is an equidigital number, since it uses as much as digits as its factorization.

131045435333353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7708555019626.

The product of its (nonzero) digits is 4374000, while the sum is 46.

Adding to 131045435333353 its reverse (353333534540131), we get a palindrome (484378969873484).

The spelling of 131045435333353 in words is "one hundred thirty-one trillion, forty-five billion, four hundred thirty-five million, three hundred thirty-three thousand, three hundred fifty-three".