Base | Representation |
---|---|
bin | 10011000100100000001… |
… | …001010100101111010011 |
3 | 11122021122022010020100220 |
4 | 103010200021110233103 |
5 | 132432403102343220 |
6 | 2442012024044123 |
7 | 163452343045533 |
oct | 23044011245723 |
9 | 4567568106326 |
10 | 1310504340435 |
11 | 465866598684 |
12 | 191b99303643 |
13 | 967704294b4 |
14 | 476006b34c3 |
15 | 24151207540 |
hex | 13120254bd3 |
1310504340435 has 16 divisors (see below), whose sum is σ = 2101112514816. Its totient is φ = 697500458208.
The previous prime is 1310504340413. The next prime is 1310504340487. The reversal of 1310504340435 is 5340434050131.
It is not a de Polignac number, because 1310504340435 - 25 = 1310504340403 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1310504340396 and 1310504340405.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 89691829 + ... + 89706438.
It is an arithmetic number, because the mean of its divisors is an integer number (131319532176).
Almost surely, 21310504340435 is an apocalyptic number.
1310504340435 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1310504340435 is a deficient number, since it is larger than the sum of its proper divisors (790608174381).
1310504340435 is a wasteful number, since it uses less digits than its factorization.
1310504340435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 179398762.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 1310504340435 its reverse (5340434050131), we get a palindrome (6650938390566).
The spelling of 1310504340435 in words is "one trillion, three hundred ten billion, five hundred four million, three hundred forty thousand, four hundred thirty-five".
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