13105525040331 has 16 divisors (see below), whose sum is σ = 17735874825600. Its totient is φ = 8607008314688.

The previous prime is 13105525040317. The next prime is 13105525040341. The reversal of 13105525040331 is 13304052550131.

It is a cyclic number.

It is not a de Polignac number, because 13105525040331 - 2⁹ = 13105525039819 is a prime.

It is a super-2 number, since 2×13105525040331² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13105525040292 and 13105525040301.

It is not an unprimeable number, because it can be changed into a prime (13105525040341) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 113984946 + ... + 114099863.

It is an arithmetic number, because the mean of its divisors is an integer number (1108492176600).

Almost surely, 2^{13105525040331} is an apocalyptic number.

13105525040331 is a deficient number, since it is larger than the sum of its proper divisors (4630349785269).

13105525040331 is a wasteful number, since it uses less digits than its factorization.

13105525040331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 228085098.

The product of its (nonzero) digits is 27000, while the sum is 33.

Adding to 13105525040331 its reverse (13304052550131), we get a palindrome (26409577590462).

The spelling of 13105525040331 in words is "thirteen trillion, one hundred five billion, five hundred twenty-five million, forty thousand, three hundred thirty-one".