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13107588560641 = 19689873082139
BaseRepresentation
bin1011111010111101100100…
…1010001111011100000001
31201102001222101100200201201
42332233121022033130001
53204223320132420031
643513313144501201
72521664156312401
oct276573112173401
951361871320651
1013107588560641
1141a3996034813
121578408a7a801
1374106a6c2913
143345a6c4c801
1517ae59be8d61
hexbebd928f701

13107588560641 has 4 divisors (see below), whose sum is σ = 13797461642800. Its totient is φ = 12417715478484.

The previous prime is 13107588560579. The next prime is 13107588560663. The reversal of 13107588560641 is 14606588570131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13107588560641 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13107588560141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 344936541051 + ... + 344936541088.

It is an arithmetic number, because the mean of its divisors is an integer number (3449365410700).

Almost surely, 213107588560641 is an apocalyptic number.

It is an amenable number.

13107588560641 is a deficient number, since it is larger than the sum of its proper divisors (689873082159).

13107588560641 is an equidigital number, since it uses as much as digits as its factorization.

13107588560641 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 689873082158.

The product of its (nonzero) digits is 4838400, while the sum is 55.

The spelling of 13107588560641 in words is "thirteen trillion, one hundred seven billion, five hundred eighty-eight million, five hundred sixty thousand, six hundred forty-one".

Divisors: 1 19 689873082139 13107588560641