Base | Representation |
---|---|
bin | 10011000100110111101… |
… | …111100101010101001011 |
3 | 11122022122220002022110212 |
4 | 103010313233211111023 |
5 | 132434210430331320 |
6 | 2442115205431335 |
7 | 163465221144635 |
oct | 23046757452513 |
9 | 4568586068425 |
10 | 1310900245835 |
11 | 465a4a017224 |
12 | 192089a0b54b |
13 | 9680446614b |
14 | 4763b0cda55 |
15 | 24175d5c9c5 |
hex | 13137be554b |
1310900245835 has 4 divisors (see below), whose sum is σ = 1573080295008. Its totient is φ = 1048720196664.
The previous prime is 1310900245789. The next prime is 1310900245841. The reversal of 1310900245835 is 5385420090131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1310900245835 - 210 = 1310900244811 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1310900245792 and 1310900245801.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131090024579 + ... + 131090024588.
It is an arithmetic number, because the mean of its divisors is an integer number (393270073752).
Almost surely, 21310900245835 is an apocalyptic number.
1310900245835 is a deficient number, since it is larger than the sum of its proper divisors (262180049173).
1310900245835 is an equidigital number, since it uses as much as digits as its factorization.
1310900245835 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 262180049172.
The product of its (nonzero) digits is 129600, while the sum is 41.
The spelling of 1310900245835 in words is "one trillion, three hundred ten billion, nine hundred million, two hundred forty-five thousand, eight hundred thirty-five".
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