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1310981272585 = 5262196254517
BaseRepresentation
bin10011000100111100100…
…100101011010000001001
311122022212112112220021121
4103010330210223100021
5132434342201210320
62442131222235241
7163500223645345
oct23047444532011
94568775486247
101310981272585
11465a90829886
121920b0b85b21
139681819597a
1447647b82625
152417d0158aa
hex1313c92b409

1310981272585 has 4 divisors (see below), whose sum is σ = 1573177527108. Its totient is φ = 1048785018064.

The previous prime is 1310981272583. The next prime is 1310981272703. The reversal of 1310981272585 is 5852721890131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 675598514704 + 635382757881 = 821948^2 + 797109^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310981272585 - 21 = 1310981272583 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310981272583) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131098127254 + ... + 131098127263.

It is an arithmetic number, because the mean of its divisors is an integer number (393294381777).

Almost surely, 21310981272585 is an apocalyptic number.

It is an amenable number.

1310981272585 is a deficient number, since it is larger than the sum of its proper divisors (262196254523).

1310981272585 is an equidigital number, since it uses as much as digits as its factorization.

1310981272585 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 262196254522.

The product of its (nonzero) digits is 1209600, while the sum is 52.

The spelling of 1310981272585 in words is "one trillion, three hundred ten billion, nine hundred eighty-one million, two hundred seventy-two thousand, five hundred eighty-five".

Divisors: 1 5 262196254517 1310981272585