1311000010001 has 4 divisors (see below), whose sum is σ = 1430181829104. Its totient is φ = 1191818190900.

The previous prime is 1311000009997. The next prime is 1311000010003. The reversal of 1311000010001 is 1000100001131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1311000010001 - 2² = 1311000009997 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311000010003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59590909535 + ... + 59590909556.

It is an arithmetic number, because the mean of its divisors is an integer number (357545457276).

Almost surely, 2^{1311000010001} is an apocalyptic number.

1311000010001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1311000010001 is a deficient number, since it is larger than the sum of its proper divisors (119181819103).

1311000010001 is a wasteful number, since it uses less digits than its factorization.

1311000010001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 119181819102.

The product of its (nonzero) digits is 3, while the sum is 8.

Adding to 1311000010001 its reverse (1000100001131), we get a palindrome (2311100011132).

The spelling of 1311000010001 in words is "one trillion, three hundred eleven billion, ten thousand, one".