1311004051 has 4 divisors (see below), whose sum is σ = 1498290352. Its totient is φ = 1123717752.

The previous prime is 1311004027. The next prime is 1311004061. The reversal of 1311004051 is 1504001131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1504001131 = 79 ⋅19037989.

It is a cyclic number.

It is not a de Polignac number, because 1311004051 - 2⁷ = 1311003923 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311004001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93643140 + ... + 93643153.

It is an arithmetic number, because the mean of its divisors is an integer number (374572588).

Almost surely, 2^1311004051 is an apocalyptic number.

1311004051 is a deficient number, since it is larger than the sum of its proper divisors (187286301).

1311004051 is an equidigital number, since it uses as much as digits as its factorization.

1311004051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 187286300.

The product of its (nonzero) digits is 60, while the sum is 16.

The square root of 1311004051 is about 36207.7899215072. The cubic root of 1311004051 is about 1094.4636562140.

Adding to 1311004051 its reverse (1504001131), we get a palindrome (2815005182).

The spelling of 1311004051 in words is "one billion, three hundred eleven million, four thousand, fifty-one".