13110100041403 has 4 divisors (see below), whose sum is σ = 13800105306760. Its totient is φ = 12420094776048.

The previous prime is 13110100041323. The next prime is 13110100041413. The reversal of 13110100041403 is 30414000101131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13110100041403 - 2¹⁷ = 13110099910331 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (19), and also a Moran number because the ratio is a prime number: 690005265337 = 13110100041403 / (1 + 3 + 1 + 1 + 0 + 1 + 0 + 0 + 0 + 4 + 1 + 4 + 0 + 3).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13110100041413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 345002632650 + ... + 345002632687.

It is an arithmetic number, because the mean of its divisors is an integer number (3450026326690).

Almost surely, 2^{13110100041403} is an apocalyptic number.

13110100041403 is a deficient number, since it is larger than the sum of its proper divisors (690005265357).

13110100041403 is an equidigital number, since it uses as much as digits as its factorization.

13110100041403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 690005265356.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 13110100041403 its reverse (30414000101131), we get a palindrome (43524100142534).

The spelling of 13110100041403 in words is "thirteen trillion, one hundred ten billion, one hundred million, forty-one thousand, four hundred three".