131101001313 has 4 divisors (see below), whose sum is σ = 174801335088. Its totient is φ = 87400667540.

The previous prime is 131101001309. The next prime is 131101001407. The reversal of 131101001313 is 313100101131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 313100101131 = 3 ⋅104366700377.

It is a cyclic number.

It is not a de Polignac number, because 131101001313 - 2² = 131101001309 is a prime.

It is a super-3 number, since 3×131101001313³ (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131101001292 and 131101001301.

It is not an unprimeable number, because it can be changed into a prime (131101001303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21850166883 + ... + 21850166888.

It is an arithmetic number, because the mean of its divisors is an integer number (43700333772).

Almost surely, 2^131101001313 is an apocalyptic number.

It is an amenable number.

131101001313 is a deficient number, since it is larger than the sum of its proper divisors (43700333775).

131101001313 is an equidigital number, since it uses as much as digits as its factorization.

131101001313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43700333774.

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 131101001313 its reverse (313100101131), we get a palindrome (444201102444).

The spelling of 131101001313 in words is "one hundred thirty-one billion, one hundred one million, one thousand, three hundred thirteen".