Base | Representation |
---|---|
bin | 1011111011000110111011… |
… | …0111111001000111110001 |
3 | 1201102022110102200221201010 |
4 | 2332301232313321013301 |
5 | 3204243441141124131 |
6 | 43514410312501133 |
7 | 2522113336112115 |
oct | 276615667710761 |
9 | 51368412627633 |
10 | 13110100333041 |
11 | 41a4a64949578 |
12 | 15789aa0aa7a9 |
13 | 74137abb458a |
14 | 334764685745 |
15 | 17b05549cb46 |
hex | bec6edf91f1 |
13110100333041 has 8 divisors (see below), whose sum is σ = 17480370473280. Its totient is φ = 8739948540752.
The previous prime is 13110100333039. The next prime is 13110100333133. The reversal of 13110100333041 is 14033300101131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13110100333041 - 21 = 13110100333039 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13110100332999 and 13110100333017.
It is not an unprimeable number, because it can be changed into a prime (13110100333021) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29328186 + ... + 29771843.
It is an arithmetic number, because the mean of its divisors is an integer number (2185046309160).
Almost surely, 213110100333041 is an apocalyptic number.
It is an amenable number.
13110100333041 is a deficient number, since it is larger than the sum of its proper divisors (4370270140239).
13110100333041 is an equidigital number, since it uses as much as digits as its factorization.
13110100333041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59173975.
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 13110100333041 its reverse (14033300101131), we get a palindrome (27143400434172).
The spelling of 13110100333041 in words is "thirteen trillion, one hundred ten billion, one hundred million, three hundred thirty-three thousand, forty-one".
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