Base | Representation |
---|---|
bin | 11000011010110110… |
… | …00100110100100011 |
3 | 1020211122222020211122 |
4 | 30031123010310203 |
5 | 203322141301311 |
6 | 10004523002455 |
7 | 642611016413 |
oct | 141533046443 |
9 | 36748866748 |
10 | 13110103331 |
11 | 5618347746 |
12 | 265a66942b |
13 | 130c1420c0 |
14 | 8c522a643 |
15 | 51ae500db |
hex | 30d6c4d23 |
13110103331 has 4 divisors (see below), whose sum is σ = 14118572832. Its totient is φ = 12101633832.
The previous prime is 13110103327. The next prime is 13110103337. The reversal of 13110103331 is 13330101131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13110103331 - 22 = 13110103327 is a prime.
It is a super-2 number, since 2×131101033312 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13110103337) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 504234731 + ... + 504234756.
It is an arithmetic number, because the mean of its divisors is an integer number (3529643208).
Almost surely, 213110103331 is an apocalyptic number.
13110103331 is a deficient number, since it is larger than the sum of its proper divisors (1008469501).
13110103331 is a wasteful number, since it uses less digits than its factorization.
13110103331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1008469500.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 13110103331 its reverse (13330101131), we get a palindrome (26440204462).
The spelling of 13110103331 in words is "thirteen billion, one hundred ten million, one hundred three thousand, three hundred thirty-one".
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