131101120113 has 4 divisors (see below), whose sum is σ = 174801493488. Its totient is φ = 87400746740.

The previous prime is 131101120063. The next prime is 131101120187. The reversal of 131101120113 is 311021101131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131101120113 - 2⁸ = 131101119857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131101120092 and 131101120101.

It is not an unprimeable number, because it can be changed into a prime (131101128113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21850186683 + ... + 21850186688.

It is an arithmetic number, because the mean of its divisors is an integer number (43700373372).

Almost surely, 2^131101120113 is an apocalyptic number.

It is an amenable number.

131101120113 is a deficient number, since it is larger than the sum of its proper divisors (43700373375).

131101120113 is an equidigital number, since it uses as much as digits as its factorization.

131101120113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43700373374.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 131101120113 its reverse (311021101131), we get a palindrome (442122221244).

The spelling of 131101120113 in words is "one hundred thirty-one billion, one hundred one million, one hundred twenty thousand, one hundred thirteen".