Base | Representation |
---|---|
bin | 10011000100111110011… |
… | …011000100110100101001 |
3 | 11122022221200221210001002 |
4 | 103010332123010310221 |
5 | 132434423122412223 |
6 | 2442134251404345 |
7 | 163501051525346 |
oct | 23047633046451 |
9 | 4568850853032 |
10 | 1311012310313 |
11 | 465aa72a89a2 |
12 | 1920bb4536b5 |
13 | 968217420a4 |
14 | 4764bd417cd |
15 | 24180ae6e28 |
hex | 1313e6c4d29 |
1311012310313 has 4 divisors (see below), whose sum is σ = 1368012845568. Its totient is φ = 1254011775060.
The previous prime is 1311012310261. The next prime is 1311012310319. The reversal of 1311012310313 is 3130132101131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1311012310313 - 26 = 1311012310249 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1311012310319) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28500267593 + ... + 28500267638.
It is an arithmetic number, because the mean of its divisors is an integer number (342003211392).
Almost surely, 21311012310313 is an apocalyptic number.
It is an amenable number.
1311012310313 is a deficient number, since it is larger than the sum of its proper divisors (57000535255).
1311012310313 is an equidigital number, since it uses as much as digits as its factorization.
1311012310313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57000535254.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 1311012310313 its reverse (3130132101131), we get a palindrome (4441144411444).
The spelling of 1311012310313 in words is "one trillion, three hundred eleven billion, twelve million, three hundred ten thousand, three hundred thirteen".
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