131101411022401 has 4 divisors (see below), whose sum is σ = 133323468836400. Its totient is φ = 128879353208404.

The previous prime is 131101411022341. The next prime is 131101411022447. The reversal of 131101411022401 is 104220114101131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131101411022401 - 2¹⁷ = 131101410891329 is a prime.

It is a super-2 number, since 2×131101411022401² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131101411025401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1111028906911 + ... + 1111028907028.

It is an arithmetic number, because the mean of its divisors is an integer number (33330867209100).

Almost surely, 2^{131101411022401} is an apocalyptic number.

It is an amenable number.

131101411022401 is a deficient number, since it is larger than the sum of its proper divisors (2222057813999).

131101411022401 is an equidigital number, since it uses as much as digits as its factorization.

131101411022401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2222057813998.

The product of its (nonzero) digits is 192, while the sum is 22.

Adding to 131101411022401 its reverse (104220114101131), we get a palindrome (235321525123532).

The spelling of 131101411022401 in words is "one hundred thirty-one trillion, one hundred one billion, four hundred eleven million, twenty-two thousand, four hundred one".