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13110143243 = 19976564919
BaseRepresentation
bin11000011010110110…
…01110100100001011
31020211200001021120212
430031123032210023
5203322144040433
610004523511335
7642611243651
oct141533164413
936750037525
1013110143243
11561837472a
12265a68854b
13130c157312
148c523add1
1551ae5bd48
hex30d6ce90b

13110143243 has 4 divisors (see below), whose sum is σ = 13116710160. Its totient is φ = 13103576328.

The previous prime is 13110143173. The next prime is 13110143251. The reversal of 13110143243 is 34234101131.

13110143243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13110143243 - 210 = 13110142219 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13110143743) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3280463 + ... + 3284456.

It is an arithmetic number, because the mean of its divisors is an integer number (3279177540).

Almost surely, 213110143243 is an apocalyptic number.

13110143243 is a deficient number, since it is larger than the sum of its proper divisors (6566917).

13110143243 is an equidigital number, since it uses as much as digits as its factorization.

13110143243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6566916.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 13110143243 its reverse (34234101131), we get a palindrome (47344244374).

The spelling of 13110143243 in words is "thirteen billion, one hundred ten million, one hundred forty-three thousand, two hundred forty-three".

Divisors: 1 1997 6564919 13110143243