Base | Representation |
---|---|
bin | 11000011010110110… |
… | …10000111101010011 |
3 | 1020211200001210000211 |
4 | 30031123100331103 |
5 | 203322144344133 |
6 | 10004524024551 |
7 | 642611314351 |
oct | 141533207523 |
9 | 36750053024 |
10 | 13110153043 |
11 | 5618381029 |
12 | 265a692157 |
13 | 130c15b910 |
14 | 8c52407d1 |
15 | 51ae5ebcd |
hex | 30d6d0f53 |
13110153043 has 4 divisors (see below), whose sum is σ = 14118626368. Its totient is φ = 12101679720.
The previous prime is 13110152987. The next prime is 13110153073. The reversal of 13110153043 is 34035101131.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13110153043 - 213 = 13110144851 is a prime.
It is a super-2 number, since 2×131101530432 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13110153073) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 504236643 + ... + 504236668.
It is an arithmetic number, because the mean of its divisors is an integer number (3529656592).
Almost surely, 213110153043 is an apocalyptic number.
13110153043 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13110153043 is a deficient number, since it is larger than the sum of its proper divisors (1008473325).
13110153043 is a wasteful number, since it uses less digits than its factorization.
13110153043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1008473324.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 13110153043 its reverse (34035101131), we get a palindrome (47145254174).
The spelling of 13110153043 in words is "thirteen billion, one hundred ten million, one hundred fifty-three thousand, forty-three".
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