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1311020013131 = 6172124829843
BaseRepresentation
bin10011000100111110111…
…000011101011001001011
311122022222020110010022122
4103010332320131121023
5132434432110410011
62442135124441455
7163501204146503
oct23047670353113
94568866403278
101311020013131
1146600068a164
12192101b4928b
139682320b17a
144764cd88a03
15241816193db
hex1313ee1d64b

1311020013131 has 4 divisors (see below), whose sum is σ = 1313144843592. Its totient is φ = 1308895182672.

The previous prime is 1311020013113. The next prime is 1311020013167. The reversal of 1311020013131 is 1313100201131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1311020013131 is a prime.

It is a super-2 number, since 2×13110200131312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311020003131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1062414305 + ... + 1062415538.

It is an arithmetic number, because the mean of its divisors is an integer number (328286210898).

Almost surely, 21311020013131 is an apocalyptic number.

1311020013131 is a deficient number, since it is larger than the sum of its proper divisors (2124830461).

1311020013131 is an equidigital number, since it uses as much as digits as its factorization.

1311020013131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2124830460.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1311020013131 its reverse (1313100201131), we get a palindrome (2624120214262).

The spelling of 1311020013131 in words is "one trillion, three hundred eleven billion, twenty million, thirteen thousand, one hundred thirty-one".

Divisors: 1 617 2124829843 1311020013131