131102030113 has 4 divisors (see below), whose sum is σ = 133324098480. Its totient is φ = 128879961748.

The previous prime is 131102030089. The next prime is 131102030117. The reversal of 131102030113 is 311030201131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131102030113 - 2⁹ = 131102029601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131102030117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1111034095 + ... + 1111034212.

It is an arithmetic number, because the mean of its divisors is an integer number (33331024620).

Almost surely, 2^131102030113 is an apocalyptic number.

It is an amenable number.

131102030113 is a deficient number, since it is larger than the sum of its proper divisors (2222068367).

131102030113 is an equidigital number, since it uses as much as digits as its factorization.

131102030113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2222068366.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 131102030113 its reverse (311030201131), we get a palindrome (442132231244).

The spelling of 131102030113 in words is "one hundred thirty-one billion, one hundred two million, thirty thousand, one hundred thirteen".