1311021536113 has 4 divisors (see below), whose sum is σ = 1388140450020. Its totient is φ = 1233902622208.

The previous prime is 1311021536089. The next prime is 1311021536137. The reversal of 1311021536113 is 3116351201131.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1311021536089) and next prime (1311021536137).

It can be written as a sum of positive squares in 2 ways, for example, as 1156500215649 + 154521320464 = 1075407^2 + 393092^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311021536113 - 2⁵ = 1311021536081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311021536183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38559456928 + ... + 38559456961.

It is an arithmetic number, because the mean of its divisors is an integer number (347035112505).

Almost surely, 2^{1311021536113} is an apocalyptic number.

It is an amenable number.

1311021536113 is a deficient number, since it is larger than the sum of its proper divisors (77118913907).

1311021536113 is an equidigital number, since it uses as much as digits as its factorization.

1311021536113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 77118913906.

The product of its (nonzero) digits is 1620, while the sum is 28.

Adding to 1311021536113 its reverse (3116351201131), we get a palindrome (4427372737244).

The spelling of 1311021536113 in words is "one trillion, three hundred eleven billion, twenty-one million, five hundred thirty-six thousand, one hundred thirteen".