1311031110113 has 4 divisors (see below), whose sum is σ = 1329496337088. Its totient is φ = 1292565883140.

The previous prime is 1311031110101. The next prime is 1311031110119. The reversal of 1311031110113 is 3110111301131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1311031110113 - 2³⁶ = 1242311633377 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311031110091 and 1311031110100.

It is not an unprimeable number, because it can be changed into a prime (1311031110119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9232613381 + ... + 9232613522.

It is an arithmetic number, because the mean of its divisors is an integer number (332374084272).

Almost surely, 2^{1311031110113} is an apocalyptic number.

It is an amenable number.

1311031110113 is a deficient number, since it is larger than the sum of its proper divisors (18465226975).

1311031110113 is an equidigital number, since it uses as much as digits as its factorization.

1311031110113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18465226974.

The product of its (nonzero) digits is 27, while the sum is 17.

Adding to 1311031110113 its reverse (3110111301131), we get a palindrome (4421142411244).

The spelling of 1311031110113 in words is "one trillion, three hundred eleven billion, thirty-one million, one hundred ten thousand, one hundred thirteen".