Base | Representation |
---|---|
bin | 1011111011000111101110… |
… | …0000111000000111101001 |
3 | 1201102100000012202020121002 |
4 | 2332301323200320013221 |
5 | 3204244404433402213 |
6 | 43514443330124345 |
7 | 2522121522511130 |
oct | 276617340700751 |
9 | 51370005666532 |
10 | 13110312403433 |
11 | 41a5063626163 |
12 | 1578a491206b5 |
13 | 7413b2b0690b |
14 | 3347848ca917 |
15 | 17b068ddd658 |
hex | bec7b8381e9 |
13110312403433 has 16 divisors (see below), whose sum is σ = 15127122422016. Its totient is φ = 11129973414720.
The previous prime is 13110312403417. The next prime is 13110312403481. The reversal of 13110312403433 is 33430421301131.
It is a cyclic number.
It is not a de Polignac number, because 13110312403433 - 24 = 13110312403417 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13110312403396 and 13110312403405.
It is not an unprimeable number, because it can be changed into a prime (13110312423433) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20263298 + ... + 20900283.
It is an arithmetic number, because the mean of its divisors is an integer number (945445151376).
Almost surely, 213110312403433 is an apocalyptic number.
It is an amenable number.
13110312403433 is a deficient number, since it is larger than the sum of its proper divisors (2016810018583).
13110312403433 is a wasteful number, since it uses less digits than its factorization.
13110312403433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41164024.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 13110312403433 its reverse (33430421301131), we get a palindrome (46540733704564).
The spelling of 13110312403433 in words is "thirteen trillion, one hundred ten billion, three hundred twelve million, four hundred three thousand, four hundred thirty-three".
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