131103300253139 has 4 divisors (see below), whose sum is σ = 131104234171080. Its totient is φ = 131102366335200.

The previous prime is 131103300253099. The next prime is 131103300253193. The reversal of 131103300253139 is 931352003301131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131103300253139 - 2⁴⁰ = 130003788625363 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131103300253099 and 131103300253108.

It is not an unprimeable number, because it can be changed into a prime (131103300253199) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 466748369 + ... + 467029170.

It is an arithmetic number, because the mean of its divisors is an integer number (32776058542770).

Almost surely, 2^{131103300253139} is an apocalyptic number.

131103300253139 is a deficient number, since it is larger than the sum of its proper divisors (933917941).

131103300253139 is an equidigital number, since it uses as much as digits as its factorization.

131103300253139 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 933917940.

The product of its (nonzero) digits is 21870, while the sum is 35.

The spelling of 131103300253139 in words is "one hundred thirty-one trillion, one hundred three billion, three hundred million, two hundred fifty-three thousand, one hundred thirty-nine".