1311033113 has 4 divisors (see below), whose sum is σ = 1411881828. Its totient is φ = 1210184400.

The previous prime is 1311033109. The next prime is 1311033133. The reversal of 1311033113 is 3113301131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 786073369 + 524959744 = 28037^2 + 22912^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311033113 - 2² = 1311033109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311033091 and 1311033100.

It is not an unprimeable number, because it can be changed into a prime (1311033103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50424338 + ... + 50424363.

It is an arithmetic number, because the mean of its divisors is an integer number (352970457).

Almost surely, 2^1311033113 is an apocalyptic number.

1311033113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1311033113 is a deficient number, since it is larger than the sum of its proper divisors (100848715).

1311033113 is a wasteful number, since it uses less digits than its factorization.

1311033113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100848714.

The product of its (nonzero) digits is 81, while the sum is 17.

The square root of 1311033113 is about 36208.1912417619. The cubic root of 1311033113 is about 1094.4717434170.

Adding to 1311033113 its reverse (3113301131), we get a palindrome (4424334244).

The spelling of 1311033113 in words is "one billion, three hundred eleven million, thirty-three thousand, one hundred thirteen".