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131103421431211 = 2932425113942309
BaseRepresentation
bin11101110011110011100100…
…110111001111110110101011
3122012012100211212002202210001
4131303303210313033312223
5114140444301341244321
61142500025204403431
736420624000133225
oct3563634467176653
9565170755082701
10131103421431211
11388567155a2119
121285487a6a6577
13581cccc14ac68
142453621c11415
15102547a5d6c91
hex773ce4dcfdab

131103421431211 has 8 divisors (see below), whose sum is σ = 135624657063600. Its totient is φ = 126582214332000.

The previous prime is 131103421431179. The next prime is 131103421431247. The reversal of 131103421431211 is 112134124301131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131103421431211 - 25 = 131103421431179 is a prime.

It is a super-3 number, since 3×1311034214312113 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131103421431211.

It is not an unprimeable number, because it can be changed into a prime (131103421431811) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2432125 + ... + 16374433.

It is an arithmetic number, because the mean of its divisors is an integer number (16953082132950).

Almost surely, 2131103421431211 is an apocalyptic number.

131103421431211 is a deficient number, since it is larger than the sum of its proper divisors (4521235632389).

131103421431211 is a wasteful number, since it uses less digits than its factorization.

131103421431211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14266589.

The product of its (nonzero) digits is 1728, while the sum is 28.

Adding to 131103421431211 its reverse (112134124301131), we get a palindrome (243237545732342).

The spelling of 131103421431211 in words is "one hundred thirty-one trillion, one hundred three billion, four hundred twenty-one million, four hundred thirty-one thousand, two hundred eleven".

Divisors: 1 29 324251 9403279 13942309 404326961 4520807635559 131103421431211