13110402011201 has 4 divisors (see below), whose sum is σ = 14302256739504. Its totient is φ = 11918547282900.

The previous prime is 13110402011141. The next prime is 13110402011249. The reversal of 13110402011201 is 10211020401131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13110402011201 - 2⁶ = 13110402011137 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13110402011201.

It is not an unprimeable number, because it can be changed into a prime (13110402011261) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 595927364135 + ... + 595927364156.

It is an arithmetic number, because the mean of its divisors is an integer number (3575564184876).

Almost surely, 2^{13110402011201} is an apocalyptic number.

13110402011201 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13110402011201 is a deficient number, since it is larger than the sum of its proper divisors (1191854728303).

13110402011201 is a wasteful number, since it uses less digits than its factorization.

13110402011201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1191854728302.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 13110402011201 its reverse (10211020401131), we get a palindrome (23321422412332).

The spelling of 13110402011201 in words is "thirteen trillion, one hundred ten billion, four hundred two million, eleven thousand, two hundred one".