Base | Representation |
---|---|
bin | 11101110011110100011011… |
… | …101000111111001111100011 |
3 | 122012012110012220101020212220 |
4 | 131303310123220333033203 |
5 | 114141003142123040120 |
6 | 1142500300314122123 |
7 | 36420655526442234 |
oct | 3563643350771743 |
9 | 565173186336786 |
10 | 131104340440035 |
11 | 38857047328046 |
12 | 12854a96420343 |
13 | 582011766b871 |
14 | 24536abcb908b |
15 | 10254d111ab40 |
hex | 773d1ba3f3e3 |
131104340440035 has 16 divisors (see below), whose sum is σ = 212422222487040. Its totient is φ = 69037222307040.
The previous prime is 131104340439949. The next prime is 131104340440111. The reversal of 131104340440035 is 530044043401131.
It is not a de Polignac number, because 131104340440035 - 210 = 131104340439011 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131104340439978 and 131104340440005.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 55318285921 + ... + 55318288290.
It is an arithmetic number, because the mean of its divisors is an integer number (13276388905440).
Almost surely, 2131104340440035 is an apocalyptic number.
131104340440035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
131104340440035 is a deficient number, since it is larger than the sum of its proper divisors (81317882047005).
131104340440035 is a wasteful number, since it uses less digits than its factorization.
131104340440035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 110636574298.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 131104340440035 its reverse (530044043401131), we get a palindrome (661148383841166).
The spelling of 131104340440035 in words is "one hundred thirty-one trillion, one hundred four billion, three hundred forty million, four hundred forty thousand, thirty-five".
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