131104341401 has 4 divisors (see below), whose sum is σ = 143022917904. Its totient is φ = 119185764900.

The previous prime is 131104341373. The next prime is 131104341413. The reversal of 131104341401 is 104143401131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131104341401 - 2¹⁰ = 131104340377 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131104341461) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5959288235 + ... + 5959288256.

It is an arithmetic number, because the mean of its divisors is an integer number (35755729476).

Almost surely, 2^131104341401 is an apocalyptic number.

131104341401 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

131104341401 is a deficient number, since it is larger than the sum of its proper divisors (11918576503).

131104341401 is a wasteful number, since it uses less digits than its factorization.

131104341401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11918576502.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 131104341401 its reverse (104143401131), we get a palindrome (235247742532).

The spelling of 131104341401 in words is "one hundred thirty-one billion, one hundred four million, three hundred forty-one thousand, four hundred one".