Base | Representation |
---|---|
bin | 1011111011001000100010… |
… | …1100011101111001010011 |
3 | 1201102100120121212102120001 |
4 | 2332302020230131321103 |
5 | 3204300333041424210 |
6 | 43514521310030431 |
7 | 2522130146262265 |
oct | 276621054357123 |
9 | 51370517772501 |
10 | 13110533545555 |
11 | 41a5167439546 |
12 | 1578aab1a8417 |
13 | 741419884144 |
14 | 3347a6013b35 |
15 | 17b07d52203a |
hex | bec88b1de53 |
13110533545555 has 16 divisors (see below), whose sum is σ = 16573403296800. Its totient is φ = 9928766764800.
The previous prime is 13110533545553. The next prime is 13110533545561. The reversal of 13110533545555 is 55554533501131.
It is not a de Polignac number, because 13110533545555 - 21 = 13110533545553 is a prime.
It is a super-3 number, since 3×131105335455553 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (13110533545553) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 52914690 + ... + 53161879.
It is an arithmetic number, because the mean of its divisors is an integer number (1035837706050).
Almost surely, 213110533545555 is an apocalyptic number.
13110533545555 is a deficient number, since it is larger than the sum of its proper divisors (3462869751245).
13110533545555 is a wasteful number, since it uses less digits than its factorization.
13110533545555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106077894.
The product of its (nonzero) digits is 1687500, while the sum is 46.
The spelling of 13110533545555 in words is "thirteen trillion, one hundred ten billion, five hundred thirty-three million, five hundred forty-five thousand, five hundred fifty-five".
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