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131110000001 = 161898098709
BaseRepresentation
bin111101000011011000…
…0111101010110000001
3110112102021121002100222
41322012300331112001
54122003130000001
6140121530152425
712321012416651
oct1720660752601
9415367532328
10131110000001
11506701a4602
12214b0582715
13c495b47076
1464baa8c361
15362552261b
hex1e86c3d581

131110000001 has 4 divisors (see below), whose sum is σ = 131118114900. Its totient is φ = 131101885104.

The previous prime is 131109999991. The next prime is 131110000013. The reversal of 131110000001 is 100000011131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 53296339600 + 77813660401 = 230860^2 + 278951^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131110000001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131110000051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4033166 + ... + 4065543.

It is an arithmetic number, because the mean of its divisors is an integer number (32779528725).

Almost surely, 2131110000001 is an apocalyptic number.

It is an amenable number.

131110000001 is a deficient number, since it is larger than the sum of its proper divisors (8114899).

131110000001 is an equidigital number, since it uses as much as digits as its factorization.

131110000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8114898.

The product of its (nonzero) digits is 3, while the sum is 8.

Adding to 131110000001 its reverse (100000011131), we get a palindrome (231110011132).

The spelling of 131110000001 in words is "one hundred thirty-one billion, one hundred ten million, one", and thus it is an aban number.

Divisors: 1 16189 8098709 131110000001