131110001233 has 4 divisors (see below), whose sum is σ = 131154134128. Its totient is φ = 131065868340.

The previous prime is 131110001137. The next prime is 131110001273. The reversal of 131110001233 is 332100011131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 332100011131 = 7 ⋅47442858733.

It is a cyclic number.

It is not a de Polignac number, because 131110001233 - 2¹³ = 131109993041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131110001273) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22061991 + ... + 22067932.

It is an arithmetic number, because the mean of its divisors is an integer number (32788533532).

Almost surely, 2^131110001233 is an apocalyptic number.

It is an amenable number.

131110001233 is a deficient number, since it is larger than the sum of its proper divisors (44132895).

131110001233 is an equidigital number, since it uses as much as digits as its factorization.

131110001233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44132894.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 131110001233 its reverse (332100011131), we get a palindrome (463210012364).

The spelling of 131110001233 in words is "one hundred thirty-one billion, one hundred ten million, one thousand, two hundred thirty-three".