1311101311123 has 4 divisors (see below), whose sum is σ = 1316541565768. Its totient is φ = 1305661056480.

The previous prime is 1311101311103. The next prime is 1311101311147. The reversal of 1311101311123 is 3211131011131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311101311123 - 2⁹ = 1311101310611 is a prime.

It is a super-2 number, since 2×1311101311123² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1311101311123.

It is not an unprimeable number, because it can be changed into a prime (1311101311103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2720126961 + ... + 2720127442.

It is an arithmetic number, because the mean of its divisors is an integer number (329135391442).

Almost surely, 2^{1311101311123} is an apocalyptic number.

1311101311123 is a deficient number, since it is larger than the sum of its proper divisors (5440254645).

1311101311123 is an equidigital number, since it uses as much as digits as its factorization.

1311101311123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5440254644.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 1311101311123 its reverse (3211131011131), we get a palindrome (4522232322254).

The spelling of 1311101311123 in words is "one trillion, three hundred eleven billion, one hundred one million, three hundred eleven thousand, one hundred twenty-three".