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13111031120003 = 37934593749657
BaseRepresentation
bin1011111011001010011001…
…0110100100000010000011
31201102101212022010211101022
42332302212112210002003
53204302342431320003
643515042522500055
72522145400504535
oct276624626440203
951371768124338
1013111031120003
1141a53a22995a3
12157900996462b
1374149899a1ab
14334812137855
1517b0ac05b738
hexbeca65a4083

13111031120003 has 4 divisors (see below), whose sum is σ = 13145624870040. Its totient is φ = 13076437369968.

The previous prime is 13111031119981. The next prime is 13111031120017. The reversal of 13111031120003 is 30002113011131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13111031120003 - 26 = 13111031119939 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13111031129003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17296874450 + ... + 17296875207.

It is an arithmetic number, because the mean of its divisors is an integer number (3286406217510).

Almost surely, 213111031120003 is an apocalyptic number.

13111031120003 is a deficient number, since it is larger than the sum of its proper divisors (34593750037).

13111031120003 is an equidigital number, since it uses as much as digits as its factorization.

13111031120003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34593750036.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13111031120003 its reverse (30002113011131), we get a palindrome (43113144131134).

The spelling of 13111031120003 in words is "thirteen trillion, one hundred eleven billion, thirty-one million, one hundred twenty thousand, three".

Divisors: 1 379 34593749657 13111031120003