13111032030001 has 4 divisors (see below), whose sum is σ = 13112306316900. Its totient is φ = 13109757743104.

The previous prime is 13111032029983. The next prime is 13111032030013. The reversal of 13111032030001 is 10003023011131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10015174184976 + 3095857845025 = 3164676^2 + 1759505^2 .

It is a cyclic number.

It is not a de Polignac number, because 13111032030001 - 2²¹ = 13111029932849 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13111032030071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 637128016 + ... + 637148593.

It is an arithmetic number, because the mean of its divisors is an integer number (3278076579225).

Almost surely, 2^{13111032030001} is an apocalyptic number.

It is an amenable number.

13111032030001 is a deficient number, since it is larger than the sum of its proper divisors (1274286899).

13111032030001 is a wasteful number, since it uses less digits than its factorization.

13111032030001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1274286898.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 13111032030001 its reverse (10003023011131), we get a palindrome (23114055041132).

The spelling of 13111032030001 in words is "thirteen trillion, one hundred eleven billion, thirty-two million, thirty thousand, one".