Base | Representation |
---|---|
bin | 1011111011001010110001… |
… | …0011100111011110111001 |
3 | 1201102102010021002211001220 |
4 | 2332302230103213132321 |
5 | 3204303044014323001 |
6 | 43515100451502253 |
7 | 2522151022534122 |
oct | 276625423473671 |
9 | 51372107084056 |
10 | 13111131011001 |
11 | 41a5443716141 |
12 | 15790372b7989 |
13 | 7414b35a31aa |
14 | 3348214db049 |
15 | 17b0b5bddc36 |
hex | becac4e77b9 |
13111131011001 has 4 divisors (see below), whose sum is σ = 17481508014672. Its totient is φ = 8740754007332.
The previous prime is 13111131010997. The next prime is 13111131011009. The reversal of 13111131011001 is 10011013111131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13111131011001 - 22 = 13111131010997 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13111131011009) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2185188501831 + ... + 2185188501836.
It is an arithmetic number, because the mean of its divisors is an integer number (4370377003668).
Almost surely, 213111131011001 is an apocalyptic number.
It is an amenable number.
13111131011001 is a deficient number, since it is larger than the sum of its proper divisors (4370377003671).
13111131011001 is an equidigital number, since it uses as much as digits as its factorization.
13111131011001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4370377003670.
The product of its (nonzero) digits is 9, while the sum is 15.
Adding to 13111131011001 its reverse (10011013111131), we get a palindrome (23122144122132).
The spelling of 13111131011001 in words is "thirteen trillion, one hundred eleven billion, one hundred thirty-one million, eleven thousand, one".
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