13111131012113 has 4 divisors (see below), whose sum is σ = 13116717350640. Its totient is φ = 13105544673588.

The previous prime is 13111131012079. The next prime is 13111131012157. The reversal of 13111131012113 is 31121013111131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13111131012113 - 2¹⁶ = 13111130946577 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13111131012163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2793165743 + ... + 2793170436.

It is an arithmetic number, because the mean of its divisors is an integer number (3279179337660).

Almost surely, 2^{13111131012113} is an apocalyptic number.

It is an amenable number.

13111131012113 is a deficient number, since it is larger than the sum of its proper divisors (5586338527).

13111131012113 is an equidigital number, since it uses as much as digits as its factorization.

13111131012113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5586338526.

The product of its (nonzero) digits is 54, while the sum is 20.

Adding to 13111131012113 its reverse (31121013111131), we get a palindrome (44232144123244).

The spelling of 13111131012113 in words is "thirteen trillion, one hundred eleven billion, one hundred thirty-one million, twelve thousand, one hundred thirteen".