1311114401 has 4 divisors (see below), whose sum is σ = 1311195204. Its totient is φ = 1311033600.

The previous prime is 1311114377. The next prime is 1311114407. The reversal of 1311114401 is 1044111131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 31192225 + 1279922176 = 5585^2 + 35776^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311114401 - 2¹⁴ = 1311098017 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1311114401.

It is not an unprimeable number, because it can be changed into a prime (1311114407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6680 + ... + 51641.

It is an arithmetic number, because the mean of its divisors is an integer number (327798801).

Almost surely, 2^1311114401 is an apocalyptic number.

It is an amenable number.

1311114401 is a deficient number, since it is larger than the sum of its proper divisors (80803).

1311114401 is an equidigital number, since it uses as much as digits as its factorization.

1311114401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 80802.

The product of its (nonzero) digits is 48, while the sum is 17.

The square root of 1311114401 is about 36209.3137327953. The cubic root of 1311114401 is about 1094.4943631305.

Adding to 1311114401 its reverse (1044111131), we get a palindrome (2355225532).

The spelling of 1311114401 in words is "one billion, three hundred eleven million, one hundred fourteen thousand, four hundred one".