13111201003011 has 4 divisors (see below), whose sum is σ = 17481601337352. Its totient is φ = 8740800668672.

The previous prime is 13111201003001. The next prime is 13111201003013. The reversal of 13111201003011 is 11030010211131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13111201003011 - 2⁵ = 13111201002979 is a prime.

It is a super-3 number, since 3×13111201003011³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (13111201003013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2185200167166 + ... + 2185200167171.

It is an arithmetic number, because the mean of its divisors is an integer number (4370400334338).

Almost surely, 2^{13111201003011} is an apocalyptic number.

13111201003011 is a deficient number, since it is larger than the sum of its proper divisors (4370400334341).

13111201003011 is an equidigital number, since it uses as much as digits as its factorization.

13111201003011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4370400334340.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 13111201003011 its reverse (11030010211131), we get a palindrome (24141211214142).

The spelling of 13111201003011 in words is "thirteen trillion, one hundred eleven billion, two hundred one million, three thousand, eleven".