1311121113 has 4 divisors (see below), whose sum is σ = 1748161488. Its totient is φ = 874080740.

The previous prime is 1311121111. The next prime is 1311121153. The reversal of 1311121113 is 3111211131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1311121113 - 2¹ = 1311121111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1311121092 and 1311121101.

It is not an unprimeable number, because it can be changed into a prime (1311121111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218520183 + ... + 218520188.

It is an arithmetic number, because the mean of its divisors is an integer number (437040372).

Almost surely, 2^1311121113 is an apocalyptic number.

It is an amenable number.

1311121113 is a deficient number, since it is larger than the sum of its proper divisors (437040375).

1311121113 is an equidigital number, since it uses as much as digits as its factorization.

1311121113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 437040374.

The product of its digits is 18, while the sum is 15.

The square root of 1311121113 is about 36209.4064160130. The cubic root of 1311121113 is about 1094.4962308124.

Adding to 1311121113 its reverse (3111211131), we get a palindrome (4422332244).

The spelling of 1311121113 in words is "one billion, three hundred eleven million, one hundred twenty-one thousand, one hundred thirteen".